b^2+300-90000=0

Solution for b^2+300-90000=0 equation:

b^2+300-90000=0

We add all the numbers together, and all the variables

b^2-89700=0

a = 1; b = 0; c = -89700;
Δ = b2-4ac
Δ = 02-4·1·(-89700)
Δ = 358800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{358800}=\sqrt{400*897}=\sqrt{400}*\sqrt{897}=20\sqrt{897}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{897}}{2*1}=\frac{0-20\sqrt{897}}{2}
=-\frac{20\sqrt{897}}{2}
=-10\sqrt{897}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{897}}{2*1}=\frac{0+20\sqrt{897}}{2}
=\frac{20\sqrt{897}}{2}
=10\sqrt{897}
$